I converted all the units to meters initially, and the final 10^3 power is to convert from meters to millimeters.
Saturday, November 10, 2007
MP8-1: Problem 22.4 (spoiler)
For this problem use the so-called "small angle approximation" or sin x = tan x = x. So you can replace sin (theta) with just theta in the interference equation, and solve for d, the spacing between the two slits.
I converted all the units to meters initially, and the final 10^3 power is to convert from meters to millimeters.
I converted all the units to meters initially, and the final 10^3 power is to convert from meters to millimeters.
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2 comments:
is this problem similiar to the question that askes in the homework. if Dadj = lamda/2 than d would be thetha*lamda/2, lamda is the distance from the screen to the slit, and that is 2.2 m. So where do i puck in 1.6 mm to find the distance between the slits.
Hi I can help you with this in class, I'm not sure what you're asking but thanks for posting a comment.
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